You want to find the equation for a line that passes through the point (8,6) and has a slope of .
First of all, remember what the equation of a line is:
y = mx+b
Where:
m is the slope, and
b is the y-intercept
To start, you know what m is; it's just the slope, which you said was . So you can right away fill in the equation for a line somewhat to read:
y=x+b.
Now, what about b, the y-intercept?
To find b, think about what your (x,y) point means:
(8,6). When x of the line is 8, y of the line must be 6.
Because you said the line passes through this point, right?
Now, look at our line's equation so far: . b is what we want, the 0 is already set and x and y are just two "free variables" sitting there. We can plug anything we want in for x and y here, but we want the equation for the line that specfically passes through the the point (8,6).
So, why not plug in for x the number 8 and for y the number 6? This will allow us to solve for b for the particular line that passes through the point you gave!.
(8,6). y=mx+b or 6=0 × 8+b, or solving for b: b=6-(0)(8). b=6.
The equation of the line that passes through the point (8,6) with a slope of 0
is
y=+6